![]() The grep command's -w option is explained in the man page as searching for "the expression as a word as if surrounded by \" and it does just that. If you want to find instances of "I want cats" in a large file of personal aspirations while avoiding "I want catsup", either of these commands would work just fine: $ cat wish-list The -x flag will restrict matches to full line matches (each PATTERN becomes PATTERN ). Asking for help, clarification, or responding to other answers. All you need to do is add the -x flag to your grep query: grep -Fxf list1.txt list2.txt > matches.txt. The -w and \ options for selecting whole words also work for phrases. Thanks for contributing an answer to Stack Overflow Please be sure to answer the question.Provide details and share your research But avoid. grep 'B.1.1.529' adjmetadata.tsv foo B.1.1.529 The only modification youll need to make to your script with this method is to add at the right spot in your grep command: /bin/bash filter data based on the selected lineages (refer to variantslineage.txt for more info) as given below. Besides, these options wouldn't have a chance of finding your target text if it appeared inside quotes or following by some character other than a blank while still clearly a whole word: $ grep -w cat program.c One thing to keep in mind is that grep only matches patterns that appear on a single. 1 In that case, Id use grep -q > - with a line anchor at the start, and an end-of-word anchor at the end. This sure beats looking for a whole word by grepping for " cat ", "^cat " and " cat$". In this example, only lines containing the word CD are printed. $ grep "\" /usr/dict/wordsĮither of these tricks will keep you from getting "catharsis" and "catatonic" when you only want lines containing "cat". Don't forget to put your expression in quotes as shown. You can also use the regular expression \ delimiters that select whole words.
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